The equation of motion of a projectile is, y = 12x – 
x 2
The horizontal component of velocity is 3 m s –1 . Given that g = 10 m s –2 , what is range of the projectile?
Text Solution
Verified by ExpertsThe correct answer is:
B
y = 12x – 
x 2 ∴12 = 
⇒ u y = 12 u x = 12 (3) = 36
Range = 
= 
= 21.6 m
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